(7t+2)(t^2-5t-3)=0

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Solution for (7t+2)(t^2-5t-3)=0 equation:


Simplifying
(7t + 2)(t2 + -5t + -3) = 0

Reorder the terms:
(2 + 7t)(t2 + -5t + -3) = 0

Reorder the terms:
(2 + 7t)(-3 + -5t + t2) = 0

Multiply (2 + 7t) * (-3 + -5t + t2)
(2(-3 + -5t + t2) + 7t * (-3 + -5t + t2)) = 0
((-3 * 2 + -5t * 2 + t2 * 2) + 7t * (-3 + -5t + t2)) = 0
((-6 + -10t + 2t2) + 7t * (-3 + -5t + t2)) = 0
(-6 + -10t + 2t2 + (-3 * 7t + -5t * 7t + t2 * 7t)) = 0
(-6 + -10t + 2t2 + (-21t + -35t2 + 7t3)) = 0

Reorder the terms:
(-6 + -10t + -21t + 2t2 + -35t2 + 7t3) = 0

Combine like terms: -10t + -21t = -31t
(-6 + -31t + 2t2 + -35t2 + 7t3) = 0

Combine like terms: 2t2 + -35t2 = -33t2
(-6 + -31t + -33t2 + 7t3) = 0

Solving
-6 + -31t + -33t2 + 7t3 = 0

Solving for variable 't'.

The solution to this equation could not be determined.

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